A) \[A{{l}_{2}}{{O}_{3}}\]
B) \[C{{u}_{2}}O\]
C) \[MgO\]
D) \[ZnO\]
E) \[FeO\]
Correct Answer: B
Solution :
In the graph of\[{{\Delta }_{r}}G{}^\circ \,vs\,T\]for formation of oxides, the\[C{{u}_{2}}O\]line is almost at the top. So, it is quite easy to reduce oxide ores of copper directly to the metal by heating with coke (both the lines of C, CO and\[C,C{{O}_{2}}\]are at much lower temperature (500-600 K). \[C{{u}_{2}}O+C\xrightarrow{{}}2Cu+CO\]
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