2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If two springs A and B with spring constants 2k and k, are stretched separately by same suspended weight, then the ratio between the work done in stretching A and B is

    A)  1 : 2                      

    B)         1 : 4                      

    C)  1 : 3                      

    D)         4 : 1

    E)  2 : 1

    Correct Answer: A

    Solution :

    \[mg=2\,K{{x}_{A}}\] \[mg=K{{x}_{B}}\] \[\frac{{{x}_{A}}}{{{x}_{B}}}=\frac{1}{2}\] \[W=Fx\] So,          \[\frac{{{W}_{A}}}{{{W}_{B}}}=\frac{F{{x}_{A}}}{F{{x}_{B}}}=\frac{1}{2}\]


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