A) 10
B) 9
C) 4
D) 7
Correct Answer: A
Solution :
\[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] (Hendersons equation) \[=5+\log \frac{0.02}{0.2}=5+\log \frac{1}{10}\] \[=5+(-1)=4\] \[pH=14-pOH=14-4=10\]You need to login to perform this action.
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