A) 0.177 V
B) 0.087 V
C) 0.059V
D) -0.177V
Correct Answer: D
Solution :
\[pH=3,\,\,[{{H}^{+}}]={{10}^{-3}}\] \[E={{E}^{o}}_{red}+0.059\,\log \,\,(ion)\] \[E=0+0.059\,\,\log \,({{10}^{-3}})\] \[E=+0.059\,(-3)=-0.177\,\,V\]You need to login to perform this action.
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