A) 0 g
B) 0.125 g
C) 1 g
D) 0.5 g
Correct Answer: B
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] Given, \[{{N}_{0}}=2\,\,g\] \[{{t}_{1/2}}=15\] days \[T=60\] days \[\Rightarrow \] \[n=\frac{60}{15}=4\] \[\therefore \] \[N=2{{\left( \frac{1}{2} \right)}^{4}}\] or \[N=0.125\,g\]You need to login to perform this action.
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