A) 2
B) 0
C) 3
D) 1
Correct Answer: C
Solution :
\[A\xrightarrow{{}}B\] Rate\[=k{{[A]}^{n}}\] \[{{(Rate)}_{1}}=k{{(0.05)}^{n}}=2\times {{10}^{-3}}\] ... (i) \[{{(Rate)}_{2}}=k{{(0.01)}^{n}}=1.6\times {{10}^{-2}}\] ... (ii) Dividing the Eq. (ii)byEq. (i). \[=\frac{{{(Rate)}_{2}}}{{{(Rate)}_{1}}}\frac{k{{(0.01)}^{n}}}{k{{(0.1)}^{n}}}\frac{1.6\times {{10}^{-2}}}{2\times {{10}^{-3}}}\] \[{{(2)}^{n}}=8\] or \[{{(2)}^{n}}={{2}^{3}}\] \[\therefore \] \[n=3\]You need to login to perform this action.
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