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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    For the equilibrium \[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] The equilibrium constant, \[{{K}_{p}}\] is equal to:

    A)  \[{{K}_{c}}={{(RT)}^{2}}\]

    B)  \[{{K}_{c}}(RT)\]

    C)  \[\frac{{{K}_{c}}}{{{(RT)}^{2}}}\]

    D)  \[{{K}_{c}}\]

    Correct Answer: A

    Solution :

    \[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] We know that \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] Hence \[\Delta n=2-4=-2\] Hence \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-2}}=\frac{{{K}_{c}}}{{{(RT)}^{2}}}\]


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