A) \[-142.5\text{ }kJ\]
B) \[+142.5\text{ }kJ\]
C) \[-285kJ\]
D) \[+285kJ\]
Correct Answer: C
Solution :
For the decomposition of 9 gm of water heat required \[=142.5kJ\] We know that the molecular weight of \[{{H}_{2}}O=2+16=18\] Therefore, heat required for decomposition of 18 gm of water \[=\frac{18}{9}\times 142.5=285kJ\] Therefore, enthalpy of formation of water \[=-285kJ\]You need to login to perform this action.
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