A) \[0.05\]
B) \[0.02\]
C) \[0.025\]
D) \[0.04\]
Correct Answer: D
Solution :
The volume of vessel \[=10d{{m}^{3}}\] \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] At equilibrium: \[PC{{l}_{5}}=\frac{0.1}{10}=0.01\] \[C{{l}_{2}}=\frac{0.2}{10}=0.02\] The equilibrium constant, \[{{K}_{C}}=\frac{[PC{{l}_{3}}][C{{l}_{2}}]}{[PC{{l}_{5}}]}\] \[=\frac{0.02\times 0.02}{0.01}=0.04\]You need to login to perform this action.
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