CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    Three fourth of the active nuclei present in a radioactive sample decay in ¾ sec. The half life of the sample is:

    A)  \[\frac{1}{2}\] sec          

    B)  1 sec

    C)  \[\frac{3}{8}\] sec

    D)  \[\frac{3}{4}\]sec

    Correct Answer: C

    Solution :

     If\[\frac{3}{4}\] part decays If means \[\frac{1}{4}\]part remain undecayed Now from the formula \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{1}{4}={{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{n}}\]so, n = 2 \[n\times {{T}_{1/2}}=t\] \[2\times {{T}_{1/2}}=\frac{3}{4}\] Thus \[{{T}_{1/2}}=\frac{3}{8}\sec \]


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