A) 2.45 J
B) 4.9 J
C) 9.8 J
D) 19.6 J
Correct Answer: A
Solution :
Mass of the block m = 1 kg Inclination \[\theta ={{60}^{o}}\] Coefficient of friction \[\mu =0.5\] Length of the plane d = 1 m (given) The force experienced by the body \[F=\mu \,mg\,\cos \theta \] \[=0.5\times 1\times 9.8\times \cos {{60}^{o}}\] \[=4.9\times 0.5=2.45N\] Therefore work done\[=F.d=2.45\times 1=2.45J\]
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