A) \[403K\]
B) \[303K\]
C) \[606\text{ }K\]
D) \[273K\]
Correct Answer: C
Solution :
The RMS velocity of \[S{{O}_{2}}\] \[=\frac{3RT}{M}\] The RMS velocity of \[{{O}_{2}}\] \[=\frac{3RT}{M}\] In case of \[S{{O}_{2}},\]\[T=303\] molecular \[wt=64\] \[\therefore \] \[\frac{3R\times 303}{64}\] In case of \[{{O}_{2}}T=?\,M=32\] \[\therefore \] \[\frac{3R\times 303}{32}=\frac{3R\times T}{64}\] \[\therefore \] \[T=\frac{64}{32}303=606\]
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