CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    In Youngs double slit experiment, the fringe width is P, If the entire arrangement is placed in a liquid of refractive index n, the fringe width becomes:

    A)  \[n\beta \]

    B)  \[\frac{\beta }{n+1}\]

    C)  \[\frac{\beta }{n-1}\]

    D)  \[\frac{\beta }{n}\]

    Correct Answer: D

    Solution :

    Fringe width  \[\beta =\frac{D\lambda }{2d}\]      (for air)           ??(1) When entire arrangement is placed in a liquid of refractive index n, then it becomes                           \[\beta =\frac{D\lambda }{2d}\]                     ???(ii) As, \[n=\frac{\lambda }{\lambda }\] so, from eq. (i) and (ii) \[\frac{\beta }{\beta }=\frac{D\lambda }{2d}\times \frac{2d}{D\lambda }\] \[\Rightarrow \] \[\beta =\frac{\beta }{n}\]


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