CET Karnataka Medical CET - Karnataka Medical Solved Paper-2008

  • question_answer
    The equation of a simple harmonic wave is given by \[y=6\]sin\[2\pi \]\[(2t-0.1\text{ }x)\], where x and y are in mm and t is in seconds. The phase difference between two particles 2 mm apart at any instant is

    A) \[18{}^\circ \]

    B)  \[36{}^\circ \]

    C)  \[54{}^\circ \]

    D)   \[72{}^\circ \]

    Correct Answer: D

    Solution :

    From the given equation \[k=0.2\pi \] \[\Rightarrow \] \[\frac{2\pi }{\lambda }=0.2\pi \] \[\Rightarrow \] \[\lambda =10mm\] \[\Delta \phi =\frac{2\pi }{\lambda }\Delta x=\frac{2\pi }{10}\times 2=\frac{2\pi }{5}={{72}^{o}}\]


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