CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    The displacement-time graph of two moving particles make angles of \[30{}^\circ \] and \[45{}^\circ \] with the JC-axis. The ratio of their velocities is

    A)  \[\sqrt{3}:2\]

    B)  1 : 1

    C)  1 : 2            

    D)  1 : \[\sqrt{3}\]

    Correct Answer: D

    Solution :

    By   the   definition,   the   slope   of displacement-time graph is velocity. i.e.,             \[v=\tan \theta \] \[\therefore \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\tan {{\theta }_{1}}}{\tan {{\theta }_{2}}}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\tan {{30}^{o}}}{\tan {{45}^{o}}}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{1}{\sqrt{3}}\]


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