A) \[100\]
B) \[90\]
C) \[180\]
D) \[80\]
Correct Answer: D
Solution :
: \[A\to B+C\] On decomposition of 1 mole of A, 1 mole of B and after completion of the reaction corresponds to 2 moles and initial pressure to 1 mole. Initial pressure of A, (i.e., \[{{p}_{\upsilon }}\]) \[=\frac{1}{2}\times 180=90mm\,\,Hg\] ?.. (i) \[\begin{matrix} {} & A\to & B+ & C \\ at\,t=0 & {{p}_{\upsilon }} & 0 & 0 \\ after\,20\,\min & {{p}_{\upsilon }}-p & p & p \\ \end{matrix}\] After 20 minutes, the total pressure = 100 mm He \[{{p}_{\upsilon }}-p+p+p=100\] \[p+p=100\] from equation (1) \[90+p=100\] \[p=(100-90)=10mm\,Hg\] So partial pressure of \[A={{p}_{\upsilon }}-p\] \[=90-10=80mm\,Hg\]
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