A) \[6.022\times {{10}^{26}}\]
B) \[6.022\times {{10}^{23}}\]
C) \[6.022\times {{10}^{19}}\]
D) \[6.022\text{ }\times {{10}^{20}}\]
Correct Answer: D
Solution :
: No. of moles \[=\frac{Mass}{Mol.\,mass}=\frac{0.018}{18}=1\times {{10}^{-3}}\] No. of moles \[=\frac{No.\,of\,molecules}{{{N}_{0}}}\] \[1\times {{10}^{-3}}=\frac{No.\,of\,molecules}{6.022\times {{10}^{23}}}=6.022\times {{10}^{h20}}\]
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