A) \[{{N}_{2}}+3{{H}_{2}}\rightleftharpoons 2N{{H}_{3}}\]
B) \[{{N}_{2}}+{{O}_{2}}\rightleftharpoons 2NO\]
C) \[PC{{l}_{5}}\rightleftharpoons PC{{l}_{3}}+C{{l}_{2}}\]
D) \[2S{{O}_{3}}\rightleftharpoons 2S{{O}_{2}}+{{O}_{2}}\]
Correct Answer: B
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] where. \[\Delta {{n}_{g}}=\] = gaseous product - gaseous reactant when \[\Delta {{n}_{g}}=0\] then, \[{{K}_{p}}={{K}_{c}}\] \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\] \[\Delta {{n}_{g}}=2-2=0\] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{0}}\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}\]You need to login to perform this action.
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