A) \[K=K'\]
B) \[K=\sqrt{K}\]
C) \[K=\sqrt{K'}\]
D) \[K\times K'=1\]
Correct Answer: B
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] From law of mass action, \[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\] ?..(i) Similarly, for reaction \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\rightleftharpoons N{{H}_{3}}\] \[K'=\frac{[N{{H}_{3}}]}{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}\] So, from Eqs.(i) and (ii) \[K'=\sqrt{K}\]You need to login to perform this action.
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