A) 2n
B) 3n
C) An
D) 5n
Correct Answer: A
Solution :
Slope of acceleration-displacement graph \[=-{{\omega }^{2}}\] \[\therefore \] \[{{\omega }^{2}}=\tan \,{{45}^{o}}=1\] \[\therefore \] \[\omega =1\] But \[\omega =\frac{2\pi }{T}=1\] \[\therefore \] \[T=2\pi \]You need to login to perform this action.
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