A) a primary amine
B) a secondary amine
C) a tertiary amine
D) a mixture of all the three
Correct Answer: D
Solution :
When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed. \[RX+N{{H}_{3}}\xrightarrow{{}}\underset{\text{pri-amine}}{\mathop{RN{{H}_{2}}}}\,+HX\] \[RN{{H}_{2}}+XR\xrightarrow{{}}\underset{\sec -\text{amine}}{\mathop{{{R}_{2}}NH}}\,+HX\] \[{{R}_{2}}NH+XR\xrightarrow{{}}\underset{\text{ter-amine}}{\mathop{{{R}_{3}}N}}\,+HX\]You need to login to perform this action.
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