A) \[n=3,l=0,m=0,\,s=-1/2\]
B) \[n=2,l=3,m=0,\,s=+1/2\]
C) \[n=3,l=1,m=0,\,s=-1/2\]
D) \[n=3,l=2,m=1,\,s=+1/2\]
Correct Answer: D
Solution :
For 3d-orbital, \[n=3\] For d-orbital, \[l=2\] and \[m=-2,-1,0,+1,+2\] \[s=\pm \frac{1}{2}\] \[\therefore \] The correct set for 3d-orbital is \[n=3,l=2,m=1,s=+\frac{1}{2}\]You need to login to perform this action.
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