A) \[2\times {{10}^{4}}J\]
B) \[2\times {{10}^{2}}J\]
C) \[2\times {{10}^{11}}J\]
D) \[2\times {{10}^{15}}J\]
Correct Answer: A
Solution :
According to formula \[W=P\,({{V}_{2}}-{{V}_{1}})\] Given : \[P=2\times {{10}^{5}}\,N\text{/}{{m}^{2}},\]\[{{V}_{1}}=50\times {{10}^{-3}}{{m}^{3}},\] \[{{V}_{2}}=150\times {{10}^{-3}}{{m}^{3}}\] \[\therefore \] \[W=2\times {{10}^{5}}(150-50)\times {{10}^{-3}}\] \[W=2\times {{10}^{5}}\times 100\times {{10}^{-3}}\] \[W=2\times {{10}^{4}}J\]
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