A) \[\frac{1}{3}A\]and 3 V
B) \[\frac{1}{6}A\] and 4V
C) \[\frac{1}{9}A\]and 9 V
D) \[\frac{1}{2}A\]and 12 V
Correct Answer: A
Solution :
Applying Kirchhoffs voltage law in the given loop \[\Rightarrow \] \[i=\frac{1}{3}A\] Potential difference across\[PQ=\frac{1}{3}\times 9=3V\]You need to login to perform this action.
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