A) 4.58 eV
B) 2.28 eV
C) 1.14eV
D) 0.57 eV
Correct Answer: B
Solution :
\[{{W}_{0}}=\frac{12375}{{{\lambda }_{0}}(\overset{\text{o}}{\mathop{\text{A}}}\,)}\] \[=\frac{12375}{5420}=2.28\,\,eV\]You need to login to perform this action.
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