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CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    An aeroplane moves 400 m towards north, 300 m towards west and then 1200 m vertically upwards. Then, its displacement from the initial position is

    A)  1300 m                

    B)  1400 m

    C)  1500 m                

    D)  1600 m

    Correct Answer: A

    Solution :

                    \[x=400\,m,\] \[y=300\,m\]and \[z=1200\,m\] \[r=\sqrt{{{x}^{2}}+{{y}^{2}}+{{z}^{2}}}\] \[=\sqrt{{{(400)}^{2}}+{{(300)}^{2}}+{{(1200)}^{2}}}\] \[={{10}^{2}}\sqrt{16+9+144}\] \[=1300\,m\]


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