A) 2.02 atm
B) 1.54 atm
C) 1.02 atm
D) 5.24 atm
E) None of these
Correct Answer: B
Solution :
Since, the volume of the gas is equal to the volume of its container, therefore \[V=5L\] Further, molecular mass of\[{{O}_{2}}=32.0\] therefore, the number of moles of \[{{O}_{2}}\]gas, \[n=\frac{10}{32}mol\] and using the ideal gas equation, \[pV=nRT\] \[p=\frac{nRT}{V}=\frac{(10/32)\,(0.0821)\,(300)}{5}\] \[=1.54\,atm\]You need to login to perform this action.
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