A) 5
B) 10
C) 30
D) 25
E) None of these
Correct Answer: D
Solution :
Amount of starch added to 100 mL of gold to prevent coagulation of 1 mL of 10% \[NaCl\] solution = 0.25 g = 250 mg Starch required to be added to 10 mL of gold sol to completely prevent coagulation by 1 mL of 10% NaCl solution \[=\frac{250}{100}\times 10\] \[=25\,mg\] \[\therefore \] Gold number of starch = 25You need to login to perform this action.
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