A) 9.5 mA
B) 0.5 mA
C) 10.5 mA
D) \[\left( \frac{200}{19} \right)\]mA
E) None of these
Correct Answer: B
Solution :
Current gain \[\alpha =\frac{{{i}_{C}}}{{{i}_{E}}}=\frac{{{i}_{E}}-{{i}_{B}}}{{{i}_{E}}}\] \[\therefore \] \[0.95=\frac{10-{{i}_{B}}}{10}\] \[10-{{i}_{B}}=0.95\times 10\] \[10-{{i}_{B}}=9.5\] \[{{i}_{B}}=10-9.5\] \[=0.5\,mA\]You need to login to perform this action.
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