A) \[\frac{g}{R}\]
B) Rg
C) \[g{{R}^{2}}\]
D) \[\frac{g}{{{R}^{2}}}\]
E) None of these
Correct Answer: B
Solution :
Gravitational potential from the surface of earth to gravitational potential at\[\infty =0\] Potential difference\[=-\,0-\left( -\frac{GM}{R} \right)\] \[\Delta V=\frac{GM}{R}\] Work done in shifting a body of mass m kg from the surface of earth to infinity. \[W=m\Delta V\] \[=\frac{GMm}{R}\] \[\therefore \]Work done per kg\[=\frac{GM}{R}=gR\]You need to login to perform this action.
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