A) 94.39 mm
B) 141.93 mm
C) 134.44 mm
D) 199.34 mm
Correct Answer: B
Solution :
Relative lowering in vapour pressure, \[\frac{p{}^\circ -{{p}_{s}}}{p{}^\circ }=\frac{w\times M}{m\times W}\] \[\frac{143-{{p}_{s}}}{143}=\frac{0.5}{65}\times \frac{154}{1.58\times 100}\] \[\left[ \begin{align} & \because Molecular\text{ }weight\text{ }of\,CC{{l}_{4}}=154 \\ & \,\,\,\,\,and\text{ }weight=density\times volume \\ \end{align} \right]\] \[143-{{p}_{s}}=1.07\]\[\Rightarrow \] \[{{p}_{s}}=141.93\,mm\]You need to login to perform this action.
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