A) 1.70 V
B) 0.91 V
C) 1.37 V
D) 0.548 V
Correct Answer: A
Solution :
For the reaction, \[MnO_{4}^{-}+4{{H}^{+}}+3{{e}^{-}}\xrightarrow{{}}Mn{{O}_{2}}+2{{H}_{2}}O\] \[-{{E}_{3}}=\frac{-1.51\times 5+2\times 1.23}{3}\] \[\therefore \] \[{{E}_{3}}=1.70\,V\]You need to login to perform this action.
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