A) 1 : 4 : 9
B) 1 : 3 : 5
C) 1 : 2 : 3
D) 1 : 1 : 1
Correct Answer: B
Solution :
Distance travelled by the body in nth second is given by \[{{S}_{n}}=u+\frac{1}{2}g\,(2n-1)\] where u is initial velocity of body. For \[n=1\] \[{{s}_{1}}=0+\frac{1}{2}\,g(2\times 1-1)=g/2\] For \[n=2,\,{{s}_{2}}=\frac{1}{2}g(2\times 2-1)=3g/2\] For \[n=3,\,{{s}_{3}}=\frac{1}{2}g(2\times 3-1)=5g/2\] Hence, the ratio \[{{s}_{1}}:{{s}_{2}}:{{s}_{3}}=1:3:5\]You need to login to perform this action.
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