A) \[\frac{{{m}_{1}}{{m}_{2}}g}{{{m}_{1}}-{{m}_{2}}}\]
B) \[\frac{{{m}_{2}}g}{{{m}_{1}}+{{m}_{2}}}\]
C) \[\frac{{{m}_{1}}g}{{{m}_{1}}+{{m}_{2}}}\]
D) \[{{m}_{1}}{{m}_{2}}g\]
Correct Answer: B
Solution :
The free body diagram of the system is shown. T is tension in the string and a is acceleration of the blocks. From Newtons second law \[{{m}_{2}}a={{m}_{2}}g-T\] ... (i) \[T={{m}_{1}}\,\,a\] ? (ii) Solving Eqs. (i) and (ii), we get \[a=\frac{{{m}_{2}}\,g}{{{m}_{1}}+{{m}_{2}}}\]You need to login to perform this action.
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