A) sodium perchlorate
B) barium chloride
C) sodium chloride
D) barium chlorate
Correct Answer: A
Solution :
Perchloric acid is prepared by the reaction of \[\text{NaCl}{{\text{O}}_{\text{4}}}\] (sodium per chlorate) with con. \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]as, \[\underset{\begin{smallmatrix} \text{Sodium} \\ \text{perchlorate} \end{smallmatrix}}{\mathop{NaCl{{O}_{4}}}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}NaHS{{O}_{4}}+\underset{\begin{smallmatrix} \text{Perchloric} \\ \text{acid} \end{smallmatrix}}{\mathop{HCl{{O}_{4}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
