A) 2.76
B) 1.75
C) 3.86
D) zero
Correct Answer: D
Solution :
Atomic number of Sc (Scandium) is 21. Its electronic configuration is \[{{\,}_{21}}Sc=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{1}},4{{s}^{2}}\] \[S{{c}^{3+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{0}},4{{s}^{0}}\] electronic configuration of \[\text{S}{{\text{c}}^{\text{3+}}}\]ion has no unpaired electron. So, it is diamagnetic in nature. Hence, its dipole moment is zero.
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