A) 1 : 2
B) 1 : 3
C) 3 : 8
D) 3 : 4
Correct Answer: C
Solution :
First overtone of closed end pipe \[{{P}_{2}}\] = Third overtone of open end pipe\[{{P}_{2}}\] \[3\times \frac{v}{4{{l}_{c}}}=4\times \frac{v}{2{{l}_{o}}}\] \[\frac{{{l}_{o}}}{{{l}_{o}}}=\frac{3}{4}\times \frac{2}{4}=3:8\]You need to login to perform this action.
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