A) 1950 Hz
B) 2068 Hz
C) 1832 Hz
D) 2186 Hz
Correct Answer: B
Solution :
Applying Dopplers effect, if source and observer both are moving away from each other. Then, the apparent frequency heard by observer is given by \[n=\left( \frac{v-{{v}_{o}}}{v+{{v}_{s}}} \right)n\] \[\left( \begin{align} & Given:n=1950\,Hz \\ & {{v}_{o}}={{v}_{s}}=10\,m/s \\ & v=340\,m/s \\ \end{align} \right)\] \[1950=\left( \frac{340-10}{340+10} \right)n\] \[\Rightarrow \] \[n=\frac{1950}{\frac{340-10}{340+10}}=\frac{1950\times 350}{330}\] \[=2068\,Hz\]You need to login to perform this action.
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