A) zero
B) 1
C) 12
D) 6
Correct Answer: D
Solution :
Work done is given by \[W=F.s\] (Given: W = 6 joule) \[\vec{F}=3\hat{i}+\hat{j}+2\hat{k}\] \[\vec{s}=(-4\hat{i}+2\hat{j}+3\hat{k})\] \[6=(3\hat{i}+c\hat{j}+2\hat{k}).(-4\hat{i}+2\hat{j}+3\hat{k})\] \[6=-12+2c+6\] or \[2c=12\] So, \[c=6\]You need to login to perform this action.
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