A) 2.03V
B) -2.03V
C) 2.7 IV
D) -2.71 V
Correct Answer: C
Solution :
Cell reaction, \[Mg(s)+C{{u}^{2+}}(aq.)\to Cu(s)+M{{g}^{2+}}(aq.).\] In this equation Mg is oxidised and Cu is reduced. So, oxidation takes place at Mg electrode and reduction takes place at Cu electrode. EMF Of Cell \[={{E}_{cathode}}-{{E}_{anode}}\] \[={{E}_{reduction}}-{{E}_{oxidation}}\] \[=0.34-(-2.37)\] \[=0.34+2.37=2.71\,V\]You need to login to perform this action.
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