A) 0.5
B) 4.0
C) 8.0
D) 32
Correct Answer: C
Solution :
For the reaction, \[C(s)+C{{O}_{2}}(g)\rightleftharpoons 2CO(g)\] Equilibrium constant in terms of partial pressure \[({{K}_{p}})\] is given as: \[{{K}_{p}}=\frac{p_{CO}^{2}}{{{p}_{C{{O}_{2}}}}}\] (only gaseous moles are considered) \[{{P}_{CO}}=4\] \[{{P}_{C{{O}_{2}}}}=2\] \[=\frac{4\times 4}{2}=\frac{16}{2}=8\]You need to login to perform this action.
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