A) 600
B) 100
C) 60
D) 10
Correct Answer: A
Solution :
Rate constant \[k=1.155\times {{10}^{-3}}{{\sec }^{-1}}\] \[k=\frac{2.303}{t}\log \frac{a}{(a-x)}\]\[\because \]\[a=a,(a-x)=\frac{a}{2}\] \[{{t}_{1/2}}=\frac{2.303}{k}\log \frac{a}{a/2}\] \[=\frac{2.303}{1.155\times {{10}^{-3}}}\log 2\] \[=\frac{2.303}{1.155\times {{10}^{-3}}}\times 0.3010\] \[=\frac{0.693\times {{10}^{3}}}{1.155}\] \[=0.6\times {{10}^{3}}=600\sec \] or \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{1.155\times {{10}^{-3}}}\] \[=600\,\sec \]You need to login to perform this action.
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