A) \[\left( \frac{mg}{l} \right)\]
B) \[{{\left( \frac{mg}{3l} \right)}^{1/2}}\]
C) \[\left( \frac{g}{l} \right)\]
D) \[{{\left( \frac{3g}{l} \right)}^{1/2}}\]
Correct Answer: D
Solution :
According to the equation. \[mg\frac{l}{2}=\frac{1}{2}I{{\omega }^{2}}\] \[mg\frac{l}{2}=\frac{1}{2}\frac{m{{l}^{2}}}{3}{{\omega }^{2}}\] \[{{\omega }^{2}}=\frac{2\times 3mg\times l}{m{{l}^{2}}\times 2}\] \[\omega =\sqrt{\frac{3g}{l}}\]You need to login to perform this action.
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