A) 3/4
B) 4/3
C) 9/16
D) 16/9
Correct Answer: B
Solution :
Orbital velocity of satellite is given by \[{{v}_{0}}=\sqrt{\frac{GM}{R}}\Rightarrow {{v}_{o}}\propto \sqrt{\frac{1}{R}}=\frac{1}{\sqrt{R}}\] Hence, \[\frac{{{v}_{{{o}_{1}}}}}{{{v}_{{{o}_{2}}}}}=\sqrt{\frac{{{R}_{2}}}{{{R}_{1}}}}=\sqrt{\frac{16R}{9R}}=4:3\]You need to login to perform this action.
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