A) Zero
B) \[\sqrt{2}\]
C) 2
D) 4
Correct Answer: D
Solution :
\[{{I}_{1}}={{I}_{2}}=1\,W{{m}^{-2}}\] So, resultant intensity at third vertex \[I={{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}\] \[={{(\sqrt{1}+\sqrt{1})}^{2}}={{(1+1)}^{2}}=4\,W{{m}^{-2}}\]You need to login to perform this action.
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