A) mB
B) \[\frac{mB}{2}\]
C) \[\frac{mB}{4}\]
D) 2mB
Correct Answer: C
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }\frac{m}{{{d}^{2}}}\] \[\therefore \] \[F=mB\] \[=m\times \frac{{{\mu }_{0}}}{4\pi }\frac{m}{{{(2d)}^{2}}}\] \[=\frac{m}{4}B\]You need to login to perform this action.
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