A) 200 V
B) 800 V
C) 1600 V
D) 3200 V
Correct Answer: D
Solution :
From \[mg={{F}_{e}}\] \[\left( \frac{4}{3}\pi {{r}^{3}} \right)\rho g=qE=q\frac{V}{d}\] \[\Rightarrow \] \[V\propto \frac{{{r}^{3}}}{q}\] \[\therefore \] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{r_{1}^{3}{{q}_{2}}}{r_{2}^{3}{{q}_{1}}}\] or \[\frac{400}{{{V}_{2}}}=\frac{r_{1}^{3}q}{{{(2{{r}_{1}})}^{3}}q}\] or \[\frac{400}{{{V}_{2}}}=\frac{r_{1}^{3}}{8r_{1}^{3}}\] or \[{{V}_{2}}\,=3200\,\,volt\]You need to login to perform this action.
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