A) \[2\times {{10}^{6}}\]
B) 2\[\sqrt{2}\] \[\times {{10}^{6}}\]
C) 4\[\sqrt{2}\]\[\times {{10}^{6}}\]
D) 4\[\sqrt{3}\]\[\times {{10}^{6}}\]
Correct Answer: B
Solution :
Kinetic energy (E), \[\frac{1}{2}mv_{1}^{2}=2h{{v}_{0}}-h{{v}_{0}}=h{{v}_{0}}\] and \[\frac{1}{2}mv_{2}^{2}=3h{{v}_{0}}-h{{v}_{0}}=2h{{v}_{0}}\] \[\therefore \] \[\frac{1}{2}mv_{2}^{2}=2\left[ \frac{1}{2}mv_{1}^{2} \right]\] \[\Rightarrow \] \[v_{2}^{2}=2v_{1}^{2}\] or \[{{v}_{2}}=\sqrt{2{{v}_{1}}}\] or \[=\sqrt{2}\times 2\times {{10}^{6}}\] \[\Rightarrow \] \[{{v}_{2}}=2\sqrt{2}\times {{10}^{6}}m/s\]You need to login to perform this action.
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