A) 40
B) 30
C) 20
D) 10
Correct Answer: B
Solution :
Given, \[k=0.0693{{\min }^{-1}}\] \[t=?\] \[a=20\,mol\,{{L}^{-1}}\] \[a-x=2.5\,mol\,{{L}^{-1}}\] \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[t=\frac{2.303}{k}\log \frac{20}{2.5}\] \[t=\frac{2.303}{0.0693}\log 8\] \[=33.23\times 0.9030\,\min \] \[=30\min \]You need to login to perform this action.
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