A) 0.2303
B) 2.303
C) 0.693
D) 0.01
Correct Answer: A
Solution :
Given, \[A(g)\xrightarrow{{}}B(g)\](first order reaction) Initial concentration of \[A=0.2\text{ }mol\text{ }{{L}^{-1}}\] Concentration of \[\text{B}=0.18\text{ mol}\,{{\text{L}}^{-1}}\] Concentration of A after 10 min \[=0.2-0.18\] \[=0.02\text{ mol }{{\text{L}}^{-1}}\] time (r)= 10 min Rate constant, \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[=\frac{2.303}{10}\log \frac{0.2}{0.02}\] \[=0.2303\,{{\min }^{-1}}\]You need to login to perform this action.
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